(x^2+y^2-3x+2y+4)=0

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Solution for (x^2+y^2-3x+2y+4)=0 equation: 


Simplifying
(x2 + y2 + -3x + 2y + 4) = 0

Reorder the terms:
(4 + -3x + x2 + 2y + y2) = 0

Remove parenthesis around (4 + -3x + x2 + 2y + y2)
4 + -3x + x2 + 2y + y2 = 0

Solving
4 + -3x + x2 + 2y + y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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